题目内容
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[主观题]
已知正弦电流的瞬时表达式为i(t)=28.28sin(314t+30°),其电流相量表达式为()。
A.I=28.8∠30°A
B.I=20∠30°A
C.I=28.8∠120°A
D.I=288∠0°A
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A.I=28.8∠30°A
B.I=20∠30°A
C.I=28.8∠120°A
D.I=288∠0°A
A.i=5sin(0t+30°)
B.i=5sin(Wt-30°)
C.i=7.07sin(Wt+30°)
D.i=7.07sin(Wt-30°)
A.I=28.8∠30°A
B.I=20∠30°A
C.I=28.8∠120°A
D.I=28.8∠0°A
已知10Ω电阻上通过的电流i=5sin(314t+30°)A,试求电阻两端电压有效值,写出电压u正弦表达式。
A.i=5sin(100πt+30°)A
B.i=7.07sin(100πt-60°)A
C.i=10sin(200πt-60°)A
D.i=7.07sin(100t+60°)A
A.i=5sin(ωt-π/4)A
B.i=5sin(ωt+π/4)A
C.i=10sin(ωt-π/4)A
D.i=10sin(ωt+π/4)A
A.u=220sin(50t+60°)V
B.u=220sin(314t+60°)V
C.u=311sin(50t+60°)V
D.u=311sin(314t+60°)V