![](https://static.youtibao.com/asksite/comm/h5/images/m_q_title.png)
[主观题]
用推理规则证明下式: 前提 (x)(F(x)∧S(x))→(y)(M(y)→W(y)),(3y)(M(y)∧¬W(y)), 结论 (x)(F(x)→¬S(x)).
用推理规则证明下式:
前提 (x)(F(x)∧S(x))→(
y)(M(y)→W(y)),(3y)(M(y)∧¬W(y)),
结论 (x)(F(x)→¬S(x)).
查看答案
![](https://static.youtibao.com/asksite/comm/h5/images/solist_ts.png)
用推理规则证明下式:
前提 (x)(F(x)∧S(x))→(
y)(M(y)→W(y)),(3y)(M(y)∧¬W(y)),
结论 (x)(F(x)→¬S(x)).
前提:
结论:
证明过程:
(1) P
(2) US(1)
(3)¬()P(z) P(附加前提)
(4)()]P(z) T(3)E
(5)¬P(a) US(4)
(6)¬P(a)∨]R(b,a) T(5),
(7)()(¬P(z)∨]R(b,z)) UG(6)
(8)¬()(P(z)∧R(b,z)) T(7)E
(9)¬()(S(b,y)∧M(y)) T(2)(8)I
(10)()(¬S(b,y)∨¬M(y)) T(9)E
(11)()(S(b,y)→¬M(y)) T(10)E
(12) UG(11)
(13) CP